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12+22+32+…+1234567892的个位数是(  )。

单选题
2022-01-11 18:51
A、3
B、4
C、5
D、6
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正确答案
C

试题解析

原式各项的尾数按照12到92依次循环,则计算12+22+32+…+92的尾数即可,1+4+9+6+5+6+9+4+1的尾数为5,则所有数字之和的尾数为5。因此C项正确。

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12+22+32+…+1234567892的个位数是(  )。
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