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(2012)已知微分方程y′+p+(x)y=q(x)[q(x)≠0]有两个不同的特解y1(x),y2(x),则该微分方程的通解是:(c为任意常数)()

单选题
2021-12-31 03:45
A、y=c(y1-y2)
B、y=c(y1+y2)
C、y=y1+c(y1+y2)
D、y=y1+c(y1-y2)
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正确答案
D

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