欲配制500mL的0.1mol/LHCl溶液,应量取c(HCl)=11.8mol/L的浓HCl多少mL?
设应取xmL,则500mLх0.1mol/L=11.8mol/LхxmL 解方程,得x=4.24mL 4.24mL
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