公式 A = P(A/P, i, n)中的P应发生在( )。
— I have a scar on my face, so I’ve make up my mind to have a plastic surgery.
— .
— Our company is doing a customer service questionnaire .May I take you a moment?
— .
— I'd like to apply for a library card.
—
— May I use your bike for a moment?
— .
—
— Thank you. I must say I have a great staff.
公式 A = P(A/P, i, n)中的P应发生在( )。
在A与n相等时,(P/A,20%,n)和(P/A,30%,n)这两者的大小为( )。
若 A 、B 两个具有常规现金流量的方案互斥 ,其财务净现值FNPV(i) A>FNPV(i)B ,则( )。
— Oh, dear! I've just broken a window.
— .
— I saw a car crash into the tree just now.
—
public class XXK4 {
public static void main(String[] args) {
int []a={2,5,8,10,15,20};
int s=0;
for(int i=0; i<a.length; i++) s+=a[i];
System.out.println("s="+s);
}
}
public class XXK4 {
public static void main(String[] args) {
String []a={"xxk","weirong","xucong","xuxiaohua","baojuan"};
int m=0;
for(int i=0; i<a.length; i++) {
int n=a[i].length();
if(n>m) m=n;
}
System.out.println("m="+m);
}
}
public class XXK4 {
public static void main(String[] args) {
int [][]a={{2,5,8},{3,6,9},{4,5,6}};
int []b=new int[3];
int i,j;
for(i=0; i<a.length; i++)
for(j=0; j<a[i].length; j++)
b[i]+=a[i][j];
for(i=0; i<b.length; i++)
System.out.print(b[i]+" ");
}
}
class ABC {
int a,b;
public ABC(int a, int b) {this.a=a; this.b=b;}
public int compareTo(ABC x) {return a*b-x.a*x.b;}
}
public class XXK5 {
public static void main(String[] args) {
int [][]d={{3,8},{4,6},{5,6},{2,9},{6,7},{5,8}};
ABC []ar=new ABC[d.length];
int i,k=0;
for(i=0; i<ar.length; i++)
ar[i]=new ABC(d[i][0],d[i][1]);
for(i=1; i<ar.length; i++)
if(ar[i].compareTo(ar[k])>0) k=i;
System.out.println("k="+k);
}
}
—I suggest that you conduct a commodity re-inspection in a month.
—
设有n阶对称矩阵A,用一维数组s压缩存储A的下三角元素,s的下标从零开始,元素 s[26]相应于A中的元素为a 7,5。
int a=3,b=5,c=7;
if(a>b) a=b;c=a;
if(c!=a) c=b;
printf("%d,%d,%d\n",a,b,c);
其输出结果是( )。
int a=3,b=5,c=7;
if(a>b) a=b;c=a;
if(c!=a) c=b;
printf("%d,%d,%d\\n",a,b,c);
其输出结果是( )。
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