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clc;clear

w=[0.5,2];                                                              % ω=0.5、2

num=10;den=[conv(conv([1 0],[2 1]),[1 0.5 1])];

G=tf(num,den);                                                       % 求得传递函数

for j=1:length(w)

H=freqresp(G,w(j));                                                % 求得频率响应

mag=abs(H);                                                          % 求复数H的模

phase= ____________ (H)*180/pi;                          % 求复数H的幅角并把单位转化为度

disp(['w=',num2str(w(j))])

disp(['幅频=',num2str(mag)])

disp(['幅角=',num2str(phase)])

end

多选题
2021-07-17 20:02
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