计算题:某R,L串联电路,I=5A,P=400W,U=110V,f=50hz,求R,L值?
R=P/I2=400/52=16Ω Z=U//I=110/5=22Ω XL=Z2-R2=15Ω L=XC/2πf=15/2×3.14×50=0.048H R,L值分别为16Ω,0.048H
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