匀质圆盘半径为R，质量为m，沿斜面作纯滚动。已知轮心加速度为a，则圆盘个质点的惯性力向O点简化的结果是：惯性力系主矩MQO的大小等于（）。 -题库考试答案搜索网

匀质圆盘半径为R，质量为m，沿斜面作纯滚动。已知轮心加速度为a，则圆盘个质点的惯性力向O点简化的结果是：惯性力系主矩M_QO的大小等于（）。

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2021-07-17 20:17

A、<IMG src="https://s3.cn-north-1.amazonaws.com.cn/qingshuxuetang/staticQuestionImg/98c0431c-3827-44f2-985f-76f512c64272.jpg"title="1375001037988.jpg" alt="1375001037988.jpg"/>
B、<IMG src="https://s3.cn-north-1.amazonaws.com.cn/qingshuxuetang/staticQuestionImg/c65bea76-8d22-4f6b-a7ce-7a3980b4e4bc.jpg"title="1375001048644.jpg" alt="1375001048644.jpg"/>
D、1.0

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标签：大连工业大学机械设计与制造高起专理论力学作业1

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匀质圆盘半径为R，质量为m，沿斜面作纯滚动。已知轮心加速度为a，则圆盘个质点的惯性力向O点简化的结果是：惯性力系主矩MQO的大小等于（ ）。

匀质圆盘半径为R，质量为m，沿斜面作纯滚动。已知轮心加速度为a，则圆盘个质点的惯性力向O点简化的结果是：惯性力系主矩M_QO的大小等于（）。