A、<ruby>A<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>与<ruby>B<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>不相容
B、<ruby>A<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>与<ruby>B<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>相容
C、P(A<ruby>B<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>)=P(<ruby>B<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>)
D、P(A∪<ruby>B<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>)=P(<ruby>B<rp>(</rp><rt style="font-size:7px;layout-grid-mode:line">_</rt><rp>)</rp></ruby>)
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试题解析
因为A,B不相容,故P(AB)=0,故
P(AB)=P(A)-P(AB)=P(A)
P(A∪B)=P(A)+P(B)-P(AB)=P(B)