求下列方程的通解:
(1)dy/dx=1-x+y2-xy2;
(2)y′+sin[(x+y)/2]=sin[(x-y)/2];
(3);
(4)y′cosx-ysinx=sec2x;
(5)dy/dx=2y/(x-2y);
(6)xdy-[y+xy3(1+lnx)]dx=0
设函数y=y(x)由方程x^(y^2 )+y^2 lnx+4=0确定,则dy/dx=( )。
已知由方程siny+xey=0,确定y是x的函数,则dy/dx的值是:()
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