A、<img width="96" height="96" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-07-27/1e80a5af-2085-406a-98dc-da83394892d6.png">
B、<img width="97" height="97" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-07-27/8663b698-c825-4ea4-9596-379ac33fa30f.png">
C、<img width="97" height="97" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-07-27/82beb787-8c2b-42d2-9016-2180ce2960de.png">
D、<img width="100" height="100" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-07-27/c425b2aa-9964-4ec1-9991-ec80e893c2d8.png">
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正确答案
试题解析
由A
-1BA=6A+BA,知(A
-1-E)B=6E,即(A
-1-E)B/6=E,所以有B=6(A
-1-E)
-1。
因为
![](/s/tiw/p3/UpLoadImage/2020-07-27/4e43b788-7b9c-413b-99d6-ff3366ef6a5d.png)
所以有
![](/s/tiw/p3/UpLoadImage/2020-07-27/f3c0896e-c6a6-4490-a876-eda505d6460a.png)
![](/s/tiw/p3/UpLoadImage/2020-07-27/7cd305c8-137d-48aa-bc99-3ad738357671.png)
![](/s/tiw/p3/UpLoadImage/2020-07-27/f28d3773-8565-41d6-b072-5adc353cfaa9.png)
故