A、<img width="74" height="74" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-08-05/1dddd817-9526-4b2c-8cda-2002da1f1fe3.png">
B、<img width="74" height="74" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-08-05/45465c44-e4a3-4f92-a3a7-1fa07af74bdb.png">
C、<img width="74" height="74" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-08-05/012c979a-3b53-4400-b7eb-103ed89c83bb.png">
D、<img width="74" height="74" src="https://static.tiw.cn//s/tiw/p3/UpLoadImage/2020-08-05/0e16d5c7-f8b9-4998-9923-c7a2fdaedf67.png">
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正确答案
试题解析
由A
-1BA=6A+BA,知(A
-1-E)B=6E,即(A
-1-E)B/6=E,所以有B=6(A
-1-E)
-1。
因为
![](/s/tiw/p3/UpLoadImage/2020-08-05/ebb3318d-212b-4bcb-bb19-c4ef54c79fe0.png)
,所以有
![](/s/tiw/p3/UpLoadImage/2020-08-05/7871194f-fcf7-454b-8619-672476647513.png)
,
![](/s/tiw/p3/UpLoadImage/2020-08-05/d69628b0-2a9a-4cd3-8545-15198832d94b.png)
,
![](/s/tiw/p3/UpLoadImage/2020-08-05/594bcdb6-e1f4-40a3-adf4-6017ce061559.png)
,故